What is the eccentricity of the ellipse using an equation?

x^2/25+(y-3)^2/9=1.it is in the form (x^2/a^2)+(y^2/b^2)=1 there fore a^2=25,b^2=9, eccentricity is denoted by e.we know that e^2=(a^2-b^2)/a^2=(25-9)/25.=16/25 hence e^2=16/25 therefore e=4/5